(7(2x-3))/25x^(8/5)

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Solution for (7(2x-3))/25x^(8/5) equation: 


x in (-oo:+oo)

x^(8/5)*((7*(2*x-3))/25) = 0

(7*x^(8/5)*(2*x-3))/25 = 0

( 2*x-3 )

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

( 7 )

7 = 0

x belongs to the empty set

( x^(8/5) )

1*x^(8/5) = 0 // : 1

x^(8/5) = 0

x = 0

x in { 3/2, 0 }

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